Mastering the Ideal Gas Equation: Overcoming Unit Conversion Challenges
- Paul Morgan

- Oct 17
- 1 min read

Ideal Gas Equation Calculations
PV = n R T
A common obstacle for students regarding the ideal gas equation is the conversion of units.
P = Pressure (Pa)
V = Volume (m³)
n = Number of moles of gas
R = Gas Constant = 8.31 Jmol⁻¹K⁻¹
Unit Conversion
Pressure (Pascals - Pa)
Kilopascals (KPa) to Pascals (Pa)
The prefix 'Kilo' denotes a factor of 1000 or 10³
Therefore, 1 KPa = 1000 Pa
Convert KPa to Pa by multiplying by 1000
Megapascals to Pascals
The prefix 'Mega' denotes a factor of 10⁶ or 1,000,000
Therefore, 1 MPa = 10⁶ Pa
Convert MPa to Pa by multiplying by 1,000,000
Volume (m³)
dm³ to cm³
1 dm = 10 cm (×10)
Thus, 1 dm³ = 1000 cm³ (×10³)
Convert dm³ to cm³ by multiplying by 1000
m³ to cm³
1 m = 100 cm (×100)
Thus, 1 m³ = 1,000,000 cm³ (×100³)
Convert m³ to cm³ by multiplying by 1,000,000
Temperature (K)
25°C = 298 K
Convert °C to K by adding 273
Example
Calculate the volume of 64g of Oxygen gas in cm³ at a temperature of 30°C and pressure of 500 KPa. R = 8.31 Jmol⁻¹K⁻¹
1. Determine moles of Oxygen
Moles = Mass ÷ Molar mass (Mr)
Moles = 64 ÷ 32 = 2
2. Convert T and P to appropriate units
30°C = 303 K
500 KPa = 500,000 Pa
3. Apply the Ideal Gas Equation
PV = nRT
V = nRT ÷ P
V = 2×8.31×298 ÷ 500,000
V = 0.00991 m³
4. Convert m³ to cm³
V = 0.00991 m³ = 0.00991 × 1,000,000
V = 9910 cm³

























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